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Z1 z2 = (a1 − ib1) (a2 − ib2) = (a1 a2) − i(b1 b2) which is equal to z1 z2 Let us show that z1z2 = z1z2 From part (a) we have that z1z2 = (a1a2 − b1b2) i(a1 b 2 a2b1) Hence z1z2 = (a1a2 − b1b2) − i(a1 b 2 a2b1) On the other hand, z1z2 = (a1 − ib1)(a2 − ib2) = (a1a2 − b1b2) − i(a1b2 a2b1) which is equal to z1z2 SOLUTION SET I FOR –FALL 04 3 4ChemSpider ID Doublebond stereo More details Systematic name Ethyl (2Z)(2amino1,3thiazol4yl)(me thoxyimino)acetate SMILES CCOC(=O)/C(=N\OC)/c1 csc(n1)N Copy Std InChiMonoisotopic mass Da; Man Screw Picsart I Dint Image By E L I Z A B E T H Zia zpa

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